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And return value of the false has been shown.
5 <= 10;
/ True
2 <= 2;
/ True
10 <= 3;
Completely support
> (It is larger
Operator (comparison Two systems are compared, formula 1 is larger than formula 2, whether or not (the true , you appraise
whether or not or formula 1 is type 2 or less (the false).
The following example > has shown the return value of the true and the false due to the relative result.
10 > 3;
/ True
3 > 10;
Completely support
>= (above
Operator (comparison Whether or not two systems are compared, formula 1 is type 2 or more (the true), or formula 1 is smaller
than formula 2, whether or not (the false you appraise.
The following example has shown the return value of the true and the false >= due to the relative result.
10 >= 5;
/ True
2 >= 2;
/ True
3 >=10;
Explanation
/ False
/ False
/ False
/ False
Completely support
Explanation Support <> (non-equivalence
The following example has
shown the return value of
the true and the false <> due
to the relative result. 3 < >
10; / True 3 <> 3; / False
Completely support % (Surplus
For example, the following
statement sets the value of
the X to 3. X = 45 % 6;
Completely support
%= (surplus substitution
Operator (substitution When in formula
1, dividing formula 1 with formula 2,
value of surplus is substituted.
For example, the next
two formulas become
the same result.
X = X % Y Completely support
|| (logic OR)
Operator (logic Formula 1 is appraised,
when formula 1 is the false, formula 2 is
appraised. If as for the result, appraisal
of each formula or both system is the
true, it is the true, if appraisal of both
system is the false, it is the false.
With the following example, || operator
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